Hi there!
Substitute the value " h = 2 " in th' expression :-
[tex]\dfrac {-(4h - 1)}{1 + h}[/tex] = [tex]\dfrac {-(4 × 2 - 1)}{1 + 2}[/tex] = [tex]\dfrac {-(8 - 1)}{3}[/tex] = [tex]\dfrac {-(7)}{3}[/tex] = [tex]\dfrac {- 7}{3}[/tex]
Hence, The required answer is : [tex]\dfrac {- 7}{3}[/tex]
~ Hope it helps!
