Respuesta :

gmany
[tex]a^{\log_ax}=x\\\\log_ab^n=n\cdot\log_ab[/tex]


[tex]x \ \textgreater \ 0\\\\e^{\ln x^2}=2\ln8\\\\x^2=2\ln2^3\\\\x^2=3\cdot2\ln2\\\\x^2=6\ln2\to x=\sqrt{6\ln2}[/tex]
xanxan2

The answer is X=4, B

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