butterypancake5 butterypancake5
  • 18-06-2018
  • Mathematics
contestada

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Respuesta :

sparklynugget66
sparklynugget66 sparklynugget66
  • 18-06-2018
(-3,11) & (1,-3)
x1   y1     x2 y2


-3-11  -14    -7
1+3      4       2


y=-7/2x+b
11=-7/2(-3) +b
11=21/2+b
22/2=21/2+b (subtract 21/2 from each side)
1/2=b

so it would be y=-7/2x + 1/2
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