Respuesta :

[tex]\bf sin(x)=\cfrac{1}{7}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \cfrac{1}{7} \right) \\\\\\ \measuredangle x=sin^{-1}\left( \cfrac{1}{7} \right)\implies \measuredangle x \approx 8.2132107^o[/tex]

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