Respuesta :

JцstinBieber
We use log(x) - log(y) = log(x/y) and log(x) = log(y) ⇔ x = y

[tex]\displaystyle\log(x+3) - \log(x-5) = \log 2 \implies \log\left( \frac{x+3}{x-5} \right) = \log 2 \implies \\ \\ \frac{x+3}{x-5} = 2 \implies x+3 = 2(x-5) \\ \\ x = 13 [/tex]

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