A circle has equation
(x -h)^2 +(y -k)^2 = r^2
Your equation matches this with h=0, k=5, r=2√3.
The given equation is that of a circle of radius 2√3 centered at (0, 5).
_____
Since your exponents are shown without the appropriate indicator (^), we cannot tell if your "12" is supposed to be "twelve" or "one squared". We have assumed "twelve." If it is "one squared", the radius is 1, not 2√3.
