Well, you need to add 45.0⋅mL of your standard NaOH solution precisely...........
Explanation:
And first we represent the reaction by an equation:
HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
And thus there is 1:1 stoichiometry.
We use the relationship Molarity=Moles of soluteVolume of solution.
