The "point-slope" form of the equation of a straight line is:
[tex]y-y_1=m(x-x_1)\\\\(x_1;\ y_1)\ is\ a\ known\ point\\\\m\ is\ the\ slope\ of\ the\ line[/tex]
We have:
[tex]m=-3;\ (x_1;\ y_1)=(2;-2)[/tex]
Substitute
[tex]y-(-2)=-3(x-2)\\\\y+2=-3(x-2)[/tex]
Answer: B. y + 2 = -3(x - 2)
