Given the random variable X with the probability distribution: f(x) = 2x for 0 < x < 1, find the probability distribution of Y = 8x³
a) g(y) = (2/3)y⁻(⅔) 0b) g(y) = 16y³ 0c) g(y) = (1/4)y⁺(⅓) 0d) g(y) = (1/6)y⁻(⅓) 0