Calculate the change in energy for each transition,nh =3,4,5,6 and nl= 2. Show work andgive answer in Joule.
3----2: ΔE= J
4----2: ΔE= J
5----2: ΔE= J
6----2: ΔE= J
ΔE=hcRH[(1/n²)-(1/nh²)] this is the formula provided