malacath7791 malacath7791
  • 18-02-2024
  • Mathematics
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Δx = v1Δt + (1/2 aΔt^2). A) Δx = v1Δt + (1/2 aΔt^2)
B) Δx = v1Δt + (1/2 aΔt^2)
C) Δx = v1Δt + (1/2 aΔt^2)
D) Δx = v1Δt + (1/2 aΔt^2)





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