karlajallday karlajallday

20-01-2023
Chemistry

contestada

2K3N + 3CaCl2 → 6KCl + Ca3N2

1 mol K3N = 131.301 g K3N

1 mol CaCl2 = 110.984 g CaCl2

1 mol KCl = 74.551 g KCl

1 mol Ca3N2 = 148.248 g Ca3N2

How many grams of CaCl2 would it take to make 1.5 moles of KCl?

a
54.213 g
b
83.238 g
c
166.476 g
d
110.984 g

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