karlajallday karlajallday
  • 20-01-2023
  • Chemistry
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2K3N + 3CaCl2 → 6KCl + Ca3N2

1 mol K3N = 131.301 g K3N

1 mol CaCl2 = 110.984 g CaCl2

1 mol KCl = 74.551 g KCl

1 mol Ca3N2 = 148.248 g Ca3N2

How many grams of CaCl2 would it take to make 1.5 moles of KCl?

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