A chemist combusts a 5.679 g sample of C5H12 and obtains 10.42 g of CO2. The molar mass of C5H12 is 72.15 g/mol, and the molar mass of CO2 is 44.01 g/mol. What are the theoretical yield, actual yield, and percent yield of CO2?

The balanced equation is: C5H12(l) + 8O2(g) --> 5CO2 + 6H2O(l)